VGC Tiebreaker Mechanics (and probably random Wi-Fi and Wi-Fi Competitions as well as well)
I believe the truth of the second tiebreaker is:
Tiebreaker Rating = floor((total current HP of all Pokemon) * 100 / (total max HP of all Pokemon))
Thank you TRE.
Here´s my Paris round 3 situation that I described in
my (war)story:
I had: 181 HP Rhydon + 161 HP Crobat + 156 HP Latios + 185 HP Ludicolo = 683 total HP
Foe had: 141 HP Jolteon + (161-192) HP Togekiss + 152 HP Dusknoir + 328 HP Blissey = 782-813 total HP
My Ludicolo was burned and finished the battle at 162 HP.
Foe´s Blissey was Leech Seeded and finished the battle at 287 HP.
Team 1:
0/181
0/161
0/156
162/185
Team 2:
0/141
0/161-192
0/152
287/328
Tiebreaker Rating = floor((total current HP of all Pokemon) * 100 / (total max HP of all Pokemon))
Team 1 tiebreaker score = 162 * 100 / 683 = 23
Team 2 tiebreaker score = 287 * 100 / 782-813 = 35-36
So it was futile to think I stood a chance with Ludicolo against Blissey... now with this knowledge there will be even more Cresselia flying around and maybe people will start pumping more EVs into HP or something, you know, just in case.
Maybe what you should test is when exactly the game calculates this. I think you or your brother mentioned in your comment about the last turn after the timer dropped to zero being not accounted for or something?
EDIT:
TRE said:
This means beating a even moderately damaged Blissey in the second tiebreaker department is very difficult. For better or worse, your Ludicolo would have lost to 7/8th HP Blissey even if it was at full health. On the other hand, a fainted Blissey is pretty harmful to your second tiebreaker.
Oh hadn´t thought about that. You´re right, alive Blissey means you almost always win the tiebreaker, a fainted one basically means the opposite. So yeah, you could avoid this by playing your highest HP Pokémon in the back, as your last one. I know this is situational and you´re better off just beating the oponent straight up before the timer rans out.